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SAP C-ABAPD-2309 Exam Syllabus Topics:

Topic
Details

Topic 1

Core ABAP programming: This topic covers ABAP data types, the ABAP dictionary, modularization, exceptions SAP HANA database tables, and logical expressions, operator precedence.

Topic 2

SAP clean core extensibility and ABAP cloud: The topic explains extension pattern, extension rules, ABAP cloud development, and ABAP cloud rules.

Topic 3

ABAP core data services and data modeling: It focuses on Core Data Services (CDS) views, SAP HANA database tables, foreign key relationships, and annotations.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q10-Q15):

NEW QUESTION # 10
In this nested join below in which way is the join evaluated?

A. From the bottom to the top in the order of the on conditions:
1.
a is joined with b
2.
b is joined with c
B. From the top to the bottom in the order of the on conditions
1.
b is joined with c
2.
a is joined with b
C. From the left to the right in the order of the tables:
1.
a is joined with b
2.
b is joined with c
D. From the right to the left in the order of the tables:
1.
b is joined with c.
2.
b is joined with a.

Answer: B

Explanation:
The nested join is evaluated from the top to the bottom in the order of the ON conditions. This means that the join expression is formed by assigning each ON condition to the directly preceding JOIN from left to right.
The join expression can be parenthesized implicitly or explicitly to show the order of evaluation. In this case, the implicit parentheses are as follows:
SELECT * FROM (a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b) This means that the first join expression is b INNER JOIN c ON b~c = c~c, which joins the columns of tables b and c based on the condition that b~c equals c~c. The second join expression is a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b, which joins the columns of table a and the result of the first join expression based on the condition that a~b equals b~b. The final result set contains all combinations of rows from tables a, b, and c that satisfy both join conditions.
References: 1: SELECT, FROM JOIN - ABAP Keyword Documentation - SAP Online Help

NEW QUESTION # 11

When accessing the subclass instance through go_super, what can you do? Note: There are 2 correct answers to this question.

A. Call inherited public redefined methods.
B. Call a subclass specific public method
C. Access the inherited public components.
D. Access the inherited private components.

Answer: C,D

Explanation:
When accessing the subclass instance through go_super, you can do both of the following:
* Access the inherited private components: A subclass inherits all the private attributes and methods of its superclass, unless they are explicitly overridden by the subclass. Therefore, you can access the inherited private components of the superclass through go_super, as long as they are not hidden by other attributes or methods in the subclass12.
* Access the inherited public components: A subclass inherits all the public attributes and methods of its superclass, unless they are explicitly overridden by the subclass. Therefore, you can access the inherited public components of the superclass through go_super, as long as they are not hidden by other attributes or methods in the subclass12.
You cannot do any of the following:
* Call a subclass specific public method: A subclass does not have any public methods that are not inherited from its superclass. Therefore, you cannot call a subclass specific public method through go_super12.
* Call inherited public redefined methods: A subclass does not have any public methods that are redefined from its superclass. Therefore, you cannot call inherited public redefined methods through go_super12.
References: 1: Object Oriented - ABAP Development - Support Wiki 2: Inheritance and Instantiation - ABAP Keyword Documentation

NEW QUESTION # 12
Given the following Core Data Service View Entity Data Definition:
1 @AccessControl.authorizationCheck: #NOT_REQUIRED
2 DEFINE VIEW ENTITY demo_flight_info_join
3 AS SELECT
4 FROM scarr AS a
5 LEFT OUTER JOIN scounter AS c
6 LEFT OUTER JOIN sairport AS p
7 ON p.id = c.airport
8 ON a.carrid = c.carrid
9 {
10 a.carridAS carrier_id,
11 p.idAS airport_id,
12 c.countnumAS counter_number
13 }
In what order will the join statements be executed?

A. scarr will be joined with sairport first and the result will be joined with scounter.
B. sairport will be joined to scounter first and the result will be joined with scarr.
C. scarr will be joined with scounter first and the result will be joined with sairport.
D. scounter will be joined to sairport first and the result will be joined with scarr.

Answer: C

Explanation:
Explanation
The order in which the join statements will be executed is:
scarr will be joined with scounter first and the result will be joined with sairport.
This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.
Therefore, the join statements will be executed as follows:
First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.
Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.
References: 1: Join - ABAP Keyword Documentation

NEW QUESTION # 13
/DMO/I_Connection is a CDS view.
What variable type is connection full based on the following code? DATA connection full TYPE
/DMD/I_Connection.

A. Simple variable
B. Structure
C. Internal Table

Answer: B

Explanation:
Based on the following code, the variable type of connection_full is a structure. A structure is a complex data type that consists of a group of related data objects, called components, that have their own data types and names. A structure can be defined using the TYPES statement or based on an existing structure type, such as a CDS view entity or a CDS DDIC-based view. In this case, the variable connection_full is declared using the TYPE addition, which means that it has the same structure type as the CDS view entity /DMO/I_Connection.
The CDS view entity /DMO/I_Connection is a data model view that defines a data model based on the database table /DMO/Connection. The CDS view entity /DMO/I_Connection has the following components:
carrid, connid, airpfrom, airpto, distance, and fltime. Therefore, the variable connection_full has the same components as the CDS view entity /DMO/I_Connection, and each component has the same data type and length as the corresponding field in the database table /DMO/Connection.
References: CDS Data Model Views - ABAP Keyword Documentation, DATA - ABAP Keyword Documentation, Structure Types - ABAP Keyword Documentation

NEW QUESTION # 14
Refer to the Exhibit.

Which of the following types are permitted to be used for <source> on line #4? Note: There are 2 correct answers to this question.

A. A database table from the ABAP Dictionary
B. A database view from the ABAP Dictionary
C. A CDS DDIC-based view
D. An external view from the ABAP Dictionary

Answer: A,C

Explanation:
The <source> clause in the CDS View Entity Data Definition can be used to specify the data source for the view entity. The <source> clause can accept different types of data sources, depending on the type of the view entity1.
A database table from the ABAP Dictionary: This is a valid type of data source for a CDS View Entity Data Definition. A database table from the ABAP Dictionary is a table that is defined in the ABAP Dictionary using the keyword TABLE or TABLE OF. The name of the database table must be unique within its namespace and must not contain any special characters2.
A CDS DDIC-based view: This is also a valid type of data source for a CDS View Entity Data Definition. A CDS DDIC-based view is a view that is defined in the Core Data Services using the keyword DEFINE VIEW ENTITY. The name of the CDS DDIC-based view must be unique within its namespace and must not contain any special characters3.
You cannot do any of the following:
An external view from the ABAP Dictionary: This is not a valid type of data source for a CDS View Entity Data Definition. An external view from the ABAP Dictionary is a view that is defined in an external application using any language supported by SAP, such as SQL, PL/SQL, or Java. The name of the external view must be unique within its namespace and must not contain any special characters4.
A database view from the ABAP Dictionary: This is not a valid type of data source for a CDS View Entity Data Definition. A database view from the ABAP Dictionary is a view that is defined in an external application using any language supported by SAP, such as SQL, PL/SQL, or Java. The name of the database view must be unique within its namespace and must not contain any special characters4.

NEW QUESTION # 15
......

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